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Question
The slant height of a bucket is 45 cm and the radii of its top and bottom are 28 cm and 7 cm, respectively. The curved surface area of the bucket is
Options
4953 cm2
4952 cm2
4951 cm2
4950 cm2
Solution
4950 cm2
Let the radius of the top and bottom of the bucket be R and r and let its slant height be l.
Then, R = 28 cm, r = 7 cm, l = 45 cm
curved surface area of the bucket = πl (R + r)
`= 22/7 xx 45 xx (28 + 7) "cm"^2`
= 4950 cm2
Hence, the curved surface area of the bucket is 4950 cm2.
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