Question

The slant height of a bucket is 45 cm and the radii of its top and bottom are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

विकल्प

• 4953 cm² 

• 4952 cm² 

• 4951 cm² 

• 4950 cm² 

Answer 1

4950 cm² 

Let the radius of the top and bottom of the bucket be R and r and let its slant height be l.
Then, R = 28 cm, r = 7 cm, l  = 45 cm

curved surface area of the bucket = πl (R + r)

${\displaystyle =\frac{22}{7}\times 45\times (28+7) {\text{cm}}^2}$

= 4950 cm² 

Hence, the curved surface area of the bucket is 4950 cm².