Advertisements
Advertisements
Question
‘The sum of the ages of a boy and his sister (in years) is 25 and product of their ages is 150. Find their present ages.
Solution
Let the boy and his sister's ages be ‘x’ years and ‘y’ years, respectively
According to the question,
x + y = 25 ...(i)
and xy = 150
or, y = `150/x` ...(ii)
Using equation (ii) in equation (i), we get
`x + 150/x` = 25
⇒ x2 – 25x + 150 = 0
⇒ x2 – 15x – 10x + 150 = 0
⇒ x(x – 15) – 10(x – 15) = 0
⇒ (x – 15)(x – 10) = 0
⇒ x – 15 = 0 or x – 10 = 0
⇒ x = 15 or x = 10
When x = 15 i.e., boy's age is 15 years.
Then, sister's age, y = `150/15` = 10 years
When x = 10 i.e, boy's age is 10 years
Then, sister's age, y = `150/10` = 15 years
RELATED QUESTIONS
Find the value of k for which the equation x2 + k(2x + k − 1) + 2 = 0 has real and equal roots.
Solve the following quadratic equation using formula method only :
`2x + 5 sqrt 3x +6= 0 `
Solve the following by reducing them to quadratic equations:
z4 - 10z2 + 9 = 0.
If a is a root of the equation x2 – (a + b)x + k = 0, find the value of k.
Find the discriminant of the following equations and hence find the nature of roots: 2x2 + 15x + 30 = 0
Discuss the nature of the roots of the following quadratic equations : `3x^2 - 4sqrt(3)x + 4` = 0
Find the nature of the roots of the following quadratic equations: `x^2 - (1)/(2)x - (1)/(2)` = 0
Find the values of k for which each of the following quadratic equation has equal roots: x2 – 2kx + 7k – 12 = 0 Also, find the roots for those values of k in each case.
Every quadratic equation has at least one real root.
Does there exist a quadratic equation whose coefficients are all distinct irrationals but both the roots are rationals? Why?