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Question
The sum of two numbers is 99. If one number is 20% more than the others, find the two numbers.
Solution
Let the one number be x.
So, the other number is 99 -x
As per the given condition,
99 - x = 20% of x + x
⇒ 99 - x = `(20)/(100)x xx + x`
⇒ 99 = `(20x)/(100) + 2x`
⇒ 99 = `(220x)/(100)`
⇒ x = `(99 xx 100)/(220)`
⇒ x = 45
and
99 - x
= 99 - 45
= 54
Hence, the numbers are 45 and 54.
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