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Question
The sum of two natural numbers is 20 while their difference is 4. Find the numbers.
Solution
Let the numbers be x and y,
∴ from the given conditions,
x + y = 20
`(+x -y = 4)/ ( 2x=24) `
x = 12
∴ 12 + y = 20 ∴ y = 8
The numbers are 12 and 8
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