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Question
The two tangents from an external points P to a circle with centre at O are PA and PB. If ∠APB = 70° then the value of ∠AOB is
Options
100°
110°
120°
130°
Solution
110°
Explanation;
Hint:
∠OAP = 90°
∠APO = 35°
∠AOP = 180 – (90 + 35)
= 180 – 125
= 55
∠AOB = 2 × 55 = 110°
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