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Question
If PR is tangent to the circle at P and O is the centre of the circle, then ∠POQ is
Options
120°
100°
110°
90°
Solution
120°
Explanation;
Hint:
Since PR is tangent of the circle.
∠QPR = 90°
∠OPQ = 90° – 60° = 30°
∠OQB = 30°
In ∆OPQ
∠P + ∠Q + ∠O = 180°
30 + 30° + ∠O = 180° ...(OP and OQ are equal radius)
∠O = 180° – 60° = 120°
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