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The value of p for 512 – 492 = 100p is 2. - Mathematics

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Question

The value of p for 512 – 492 = 100p is 2.

Options

  • True

  • False

MCQ
True or False

Solution

This statement is True.

Explanation:

Solving for p,

(51)2 – (49)2 = 100p

⇒ (50 + 1)2 – (50 – 1)2 = 100p  ...[∵ 51 = 50 + 1 and 49 = 50 – 1]

⇒ (2500 + 1 + 100) – (2500 + 1 – 100) = 100p  ...[∵ (a + b)2 = a2 + b2 + 2ab and (a – b)2 = a2 + b2 – 2ab]

⇒ 2500 + 1 + 100 – 2500 – 1 + 100 = 100p

⇒ 200 = 100p

⇒ 100p = 200

⇒ p = `200/100` = 2

The value of p is 2.

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 229]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 78. | Page 229
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