Advertisements
Advertisements
Question
Find the value of a, if pqa = (3p + q)2 – (3p – q)2
Solution
We have,
pqa = (3p + q)2 – (3p – q)2
⇒ pqa = [(3p + q) + (3p – q)][(3p + q) – (3p – q)] ...[Using the identity, a2 – b2 = (a + b)(a – b)]
⇒ pqa = [(3p + q + 3p – q)][3p + q – 3p + q]
⇒ pqa = 6p × 2q
⇒ `a = (6p xx 2q)/(pq) = ((6 xx 2)pq)/(pq)`
⇒ a = 12
APPEARS IN
RELATED QUESTIONS
(x + 4) and (x – 5) are the factors of ___________
Using the identity (a + b)(a – b) = a2 – b2, find the following product
(p + 2)(p – 2)
Evaluate the following, using suitable identity
297 × 303
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
49x2 – 36y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/8 - y^2/18`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(4x^2)/9 - (9y^2)/16`
Factorise the expression and divide them as directed:
(3x4 – 1875) ÷ (3x2 – 75)
The base of a parallelogram is (2x + 3 units) and the corresponding height is (2x – 3 units). Find the area of the parallelogram in terms of x. What will be the area of parallelogram of x = 30 units?
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
