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Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2 - Mathematics

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Question

Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)

Sum

Solution

We have,

pq2a = (4pq + 3q)2 – (4pq – 3q)

⇒ [(4pq + 3q) + (4pq – 3q)][(4pq + 3q) – (4pq – 3q)]  ...[Using the identity, a2 – b2 = (a + b)(a – b)]

⇒ (4pq + 3q + 4pq – 3q)(4pq + 3q – 4pq + 3q) 

⇒ 8pq × 6q

⇒ pq2a = 48pq2

⇒ `a = (48pq^2)/(pq^2)`

⇒ a = 48

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 238]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 114. (iv) | Page 238
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