Advertisements
Advertisements
Question
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
Solution
Let x be added to the given expression
4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)
i.e. x + 4c(– a + b + c) = 3a(a + b + c) – 2b(a – b + c)
⇒ x = 3a(a + b + c) – 2b(a – b + c) – 4c(– a + b + c)
= 3a2 + 3ab + 3ac – 2ba + 2b2 – 2bc + 4ca – 4cb – 4c2
⇒ x = 3a2 + ab + 7ac + 2b2 – 6bc – 4c2 ...[Adding the like terms]
APPEARS IN
RELATED QUESTIONS
Use a suitable identity to get the following products.
`(3a - 1/2)(3a - 1/2)`
Find the following squares by suing the identities.
(6x2 − 5y)2
Simplify (2x +5)2 − (2x − 5)2
Using identities, evaluate 9982
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 5.1 × 5.2
Expand (ax + by)2
Use an expansion formula to find the value.
(997)2
Use the formula to multiply the following.
(a + 6) (a − 6)
Use a formula to multiply of (x - 5)(x + 5).
Factorise the following expressions
x2 + 14x + 49