Advertisements
Advertisements
Question
The volume V, of a cone is equal to one third of π times the cube of the radius. Find a formula for it.
Solution
Let radius = r
Therefore, cube of radius = r3
One third of times π the cube of the radius = `(1)/(3)pi"r"^3`
As per the data: V = `(1)/(3)pi"r"^3`.
APPEARS IN
RELATED QUESTIONS
Make N the subject of formula I = `"NG"/("R" + "Ny")`
Make d the subject of formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`
Given: mx + ny = p and y = ax + b. Find x in terms of m, n, p, a and b.
If b = `(2"a")/("a" - 2)`, and c = `(4"b" - 3)/(3"b" + 4)`, then express c in terms of a.
Make x the subject of the formula y = `(1 - x^2)/(1 + x^2)`. Find x, when y = `(1)/(2)`
Make f the subject of the formula D = `sqrt((("f" + "p")/("f" - "p"))`. Find f, when D = 13 and P = 21.
Make z the subject of the formula y = `(2z + 1)/(2z - 1)`. If x = `(y + 1)/(y - 1)`, express z in terms of x, and find its value when x = 34.
Make c the subject of the formula a = b(1 + ct). Find c, when a = 1100, b = 100 and t = 4.
"The volume of a cone V is equal to the product of one third of π and square of radius r of the base and the height h". Express this statement as a formula. Make r the subject formula. Find r, when V = 1232cm3, π = `(22)/(7)`, h = 24cm.
The pressure P and volume V of a gas are connected by the formula PV = C; where C is a constant. If P = 4 when V = `2(1)/(2)`; find the value of P when V = 4?