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Question
Two coins are tossed 1000 times and the outcomes are recorded as below:
Number of heads | 2 | 1 | 0 |
Frequency | 200 | 550 | 250 |
Based on this information, the probability for at most one head is
Options
`1/5`
`1/4`
`4/5`
`3/4`
Solution
`bb(4/5)`
Explanation:
The total number of coins tossed, n(S) = 1000
Number of outcomes in which atmost one head,
n(E) = 550 + 250 = 800
= `(n(E))/(n(S))`
= `800/1000`
= `4/5`
Hence, the probability for atmost one head is `4/5`.
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