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Question
Two different dice are tossed together. Find the probability :
1) of getting a doublet
2) of getting a sum 10, of the numbers on the two dice.
Solution
The sample space S will be as follows:
| 1 | 2 | 3 | 4 | 5 | 6 | |
| 1 | (1,1) | (1,2) | (1,3) | (1,4) | (1,5) | (1,6) |
| 2 | (2,1) | (2,2) | (2,3) | (2,4) | (2,5) | (2,6) |
| 3 | (3,1) | (3,2) | (3,3) | (3,4) | (3,5) | (3,6) |
| 4 | (4,1) | (4,2) | (4,3) | (4,4) | (4,5) | (4,6) |
| 5 | (5,1) | (5,2) | (5,3) | (5,4) | (5,5) | (5,6) |
| 6 | (6,1) | (6,2) | (6,3) | (6,4) | (6,5) | (6,6) |
n(S) = 36
1) A: Getting a doublet
A = {(1,1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}
n(A) = 6
`P(A) = (n(A))/(n(s)) = 6/36 = 1/6`
2) B: Getting sum 10
B = {(5, 5), (6, 4), (4, 6)}
n(B) = 3
`P(B ) = (n(B))/(n(S)) = 3/36 = 1/12`
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