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Question
Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, then a white precipitate Z is formed alongwith a salt which turns the solution green. And when barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed alongwith colourless common salt solution.
(a) What could the metals X and Y be?
(b) Write the name and formula of salt XSO4.
(c) Write the name and formula of salt Y2SO4.
(d) What is the name and formula of white precipitate Z?
(e) Write the name and formula of the salt which turns the solution green in the first case.
Solution
(a) Metal X is copper and metal Y is sodium.
(b) The salt is copper sulphate; its formula is CuSO4.
(c) The salt is sodium sulphate; its formula is Na2SO4.
(d) Compound Z is barium sulphate; its formula is BaSO4.
(e) The salt that turns the solution green is copper chloride; its formula is CuCl2.
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