Advertisements
Advertisements
Question
Using remainder theorem, find the value of m if the polynomial f(x)= x3 + 5x2 -mx +6 leaves a remainder 2m when divided by (x-1),
Solution
x - 1 = 0 ⇒ x = 1 and remainder is 2 m
Substituting this value, we get :
f(x) = 1 × 1 × 1 + 5 × 1 × 1 - m × 1 + 6 = 2m
⇒ 3m = 12
⇒ m = 4
APPEARS IN
RELATED QUESTIONS
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
When x3 + 2x2 – kx + 4 is divided by x – 2, the remainder is k. Find the value of constant k.
What number should be added to polynomial f(x)= 12x3 + 16x2 - 5x - 8 so that the resulting polynomial is exactly divisible by (2x - 1) ?
Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x + 2
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
What number must be added to 2x3 – 7x2 + 2x so that the resulting polynomial leaves the remainder – 2 when divided by 2x – 3?
When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.
What is the remainder when x2018 + 2018 is divided by x – 1
The remainder, when x3 – x2 + x – 1 is divided by x + 1, is ______.