Advertisements
Advertisements
प्रश्न
Using remainder theorem, find the value of m if the polynomial f(x)= x3 + 5x2 -mx +6 leaves a remainder 2m when divided by (x-1),
उत्तर
x - 1 = 0 ⇒ x = 1 and remainder is 2 m
Substituting this value, we get :
f(x) = 1 × 1 × 1 + 5 × 1 × 1 - m × 1 + 6 = 2m
⇒ 3m = 12
⇒ m = 4
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 1
The polynomials ax3 + 3x2 – 3 and 2x3 – 5x + a, when divided by x – 4, leave the same remainder in each case. Find the value of a.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(54m3 + 18m2 − 27m + 5) ; (m − 3)
When x3 – 3x2 + 5x – 7 is divided by x – 2,then the remainder is
When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = 4x3 – 12x2 + 14x – 3; g(x) = 2x – 1
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 6x2 + 2x – 4, g(x) = `1 - 3/2 x`
Determine which of the following polynomials has x – 2 a factor:
4x2 + x – 2
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
