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Maharashtra State BoardSSC (English Medium) 9th Standard

Volume of a cone is 6280 cubic cm and base radius of the cone is 20 cm. Find its perpendicular height. (π = 3.14) - Geometry

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Question

Volume of a cone is 6280 cubic cm and base radius of the cone is 20 cm. Find its perpendicular height. (π = 3.14)

Sum

Solution

Here,
Radius of the base of cone (r) = 20 cm
volume of a cone is 6280 cm3

Let the perpendicular height of the cone be h cm.

∴ Volume of a cone = `1/3 πr^2h`

∴ 6280 = `1/3 × 3.14 × (20)^2 × h`

∴ 6280 = `1/3 × 3.14 × 400 × h`

∴ `(6280 × 3)/(3.14 × 400) = h`

∴ `(6280 × 3)/(314 × 4)`

∴ `(20 × 3)/4`

∴ h = 15 cm

∴ The perpendicular height of the cone is 15 cm.

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Notes

There is a printing mistake in the textbook, the base radius of the cone is 20 cm instead of 30 cm.

  Is there an error in this question or solution?
Chapter 9: Surface Area and Volume - Practice Set 9.2 [Page 119]

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Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 9 Surface Area and Volume
Practice Set 9.2 | Q 5. | Page 119

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