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Maharashtra State BoardSSC (English Medium) 9th Standard

Surface area of a cone is 188.4 sq.cm and its slant height is 10 cm. Find its perpendicular height ( π= 3.14) - Geometry

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Question

Surface area of a cone is 188.4 sq.cm and its slant height is 10 cm. Find its perpendicular height ( π= 3.14)

Sum

Solution

Let the radius of the base and perpendicular height of the cone be r cm and h cm, respectively.

Slant height of the cone, l = 10 cm

Surface area of the cone = 188.4 cm2

∴ πrl = 188.4 cm

⇒ 3.14 x r x 10 = 188.4

⇒ r = `[188.4]/[3.14 xx 10]` = 6 cm

Now,

r2 +  h2 = l2
⇒ (6)+ h2 = (10)2

⇒ 36 + h= 100

⇒ h= 100 - 36 = 64

⇒  h = `sqrt 64` = 8 cm.

Thus, the perpendicular height of the cone is 8 cm.

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Chapter 9: Surface Area and Volume - Practice Set 9.2 [Page 119]

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Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 9 Surface Area and Volume
Practice Set 9.2 | Q 6. | Page 119

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