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Maharashtra State BoardSSC (English Medium) 9th Standard

Volume of a cone is 1232 cm3 and its height is 24 cm. Find the surface area of the cone. π(π=227) - Geometry

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Question

Volume of a cone is 1232 cm3 and its height is 24 cm. Find the surface area of the cone. `( π = 22/7)`

Sum

Solution

Let the radius of the base and slant height of the cone be r cm and lcm, respectively.

Height of the cone, h = 24 cm

Volume of the cone = 1232 cm3

∴ `1/3`πr2h = 1232 cm3

∴ `1232 = 1/3 × 22/7 × r^2 × 24`

⇒ `(1232xx3xx7)/(22xx24) =  r^2    ...("Multiplying both sides by"  3xx7/22xx1/24)`

⇒ r2 = 49

⇒ r = `sqrt(49)`

 ⇒ r = 7 cm

Now,

l2 = r2 + h2

⇒ l2 = (7)+ (24)2

⇒ l2 = 49 + 576

⇒ l2 = 625

⇒ l = `sqrt 625`

⇒ l = 25 cm 

∴ Curved Surface area of the cone = πrl

= `22/7 xx 7 xx 25`

= 550 cm

Thus, the surface area of the cone is approximately 550 cm2.

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Notes

There is a printing mistake in the textbook, the Volume of a cone is 1232 cm3 instead of 1212 cm

  Is there an error in this question or solution?
Chapter 9: Surface Area and Volume - Practice Set 9.2 [Page 119]

APPEARS IN

Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 9 Surface Area and Volume
Practice Set 9.2 | Q 7. | Page 119

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