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Question
(NH4)2Cr2O7 → N2 + Cr2O3 +4H2O.
What volume of nitrogen at STP, will be evolved when 63g of ammonium dichromate is decomposed?
(H= 1, N = 14, 0 = 16, Cr = 52)
Solution
Molecular mass of ammonium dichromate = 252
Now, 252g of ammonium dichromate evolves= 22.4 L of nitrogen at STP
63g of ammonium dichromate will evolve= 22.4 x 63 /252 = 5.6L
So, 63g of ammonium dichromate will evolve 5.6L of oxygen.
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