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Question
Write the expression an- ak for the A.P. a, a + d, a + 2d, ... Hence, find the common difference of the A.P. for which
11th term is 5 and the 13th term is 79.
Solution
A.P: a, a+d, a+2d …
Here, we first need to write the expression for `a_n - a_k`
Now, as we know,
`a_n = a + (n - 1)d`
So for the nth term
`a_n = a + (n - 1)d`
Similarly for kth term
`a_k = a + (k - 1)d`
So,
`a_n - a_k = (a + nd - d) - (a + kd - d)`
= a + nd - d - a - kd + d
= nd - kd
= (n - k)d
So. `a_n - a_k = (n - k)d`
In the given problem, we are given 11th and 13th term of an A.P.
We need to find the common difference. Let us take the common difference as d and the first term as a.
Here,
`a_11 = 5`
`a_13 = 79`
Now we will find `a_11` and `a_13` using the formula `a_n = a + (n - 1)d`
So,
`a_11 = a + (11 - 1)d`
5 = a + 10d ......(1)
Also
`a_13 = a + (13 - 1)d`
5 = a + 10d ....(1)
Also
a_13 = a + (13 - 1)d
79 = a + 12d ....(2)
Solving for a and d
On subtracting (1) from (2), we get
79 - 5 = (a + 12d) - (a + 10d)
74 = a + 12d - a - 10d
74 = 2d
`d = 74/2`
d = 37
Therefore the common diffference for the A.P. is d = 37
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