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Question
Write the expression an- ak for the A.P. a, a + d, a + 2d, ... Hence, find the common difference of the A.P. for which a10 −a5 = 200
Solution
A.P: a, a+d, a+2d …
Here, we first need to write the expression for `a_n - a_k`
Now, as we know,
`a_n = a + (n - 1)d`
So for the nth term
`a_n = a + (n - 1)d`
Similarly for kth term
`a_k = a + (k - 1)d`
So,
`a_n - a_k = (a + nd - d) - (a + kd - d)`
= a + nd - d - a - kd + d
= nd - kd
= (n - k)d
So. `a_n - a_k = (n - k)d`
We are given, `a_10 - a_5 = 200`
Here
Let us take the first term as a and the common difference as d
Now, as we know,
`a_n = a + (n -1)d`
Here we find `a_30` and `a_20`
So, for 10th term,
`a_10 = a + (10 - 1)d`
= a + (9)d
Also for 5 th term
`a_5 = a + (5 - 1)d`
= a + (4)c
So
`a_10 - a_5 = (a +_ 9d)- (a + 4d)`
200 = a + 9d - a - 4d
200 = 5d
`d = 200/5`
d = 40
Therefore the common difference for the A.P. is d = 40
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