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Question
Write the IUPAC name of the following compound:
Solution
IUPAC name of the given compound is 2-methoxy-2-methylpropane.
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Write IUPAC names of the following
Give IUPAC names of the following compound:
\[\begin{array}{cc}
\phantom{..}\ce{H}\phantom{...}\ce{CH3}\phantom{.}\ce{H}\phantom{..}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\ce{H - C - C - C - H}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\phantom{.}\ce{H}\phantom{...}\ce{OH}\phantom{.}\ce{H}\phantom{.}\\
\end{array}\]
The compound HOCH2 – CH2OH is __________.
1-Propanol and 2-propanol can be best distinguished by:
The major product formed by the reaction:
\[\begin{array}{cc}
\ce{CH3CH-CH2Br ->[CH3O^-][CH3OH] is}\\
|\phantom{................}\\
\ce{CH3}\phantom{.............}
\end{array}\]
Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.
| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) |  |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) |  |
| (iv) |  |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
How can phenol be converted to aspirin?
Write IUPAC names of the following compounds:
\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3\phantom{...}OH\phantom{...}CH3}\\
\end{array}\]
