Advertisements
Advertisements
Question
You are given the following three lenses. Which two lenses will you use as an eyepiece and as an objective to construct a compound microscope?
Lenses | Power (D) | Aperture (cm) |
L1 | 3 | 8 |
L2 | 6 | 1 |
L3 | 10 | 1 |
Solution
For a compound microscope, an objective is so chosen that its aperture is small and focal length is very small whereas an eyepiece is so chosen that its aperture is large and focal length is moderate. Now,
focal length of L1, f1 = 1/3 = 0.33 m
focal length of L2, f2 = 1/6 = 0.166 m
focal length of L3, f3 = 1/10 = 0.1 m
Therefore, from the above calculation of focal length and given aperture, it shows that L1 will be suitable for eyepiece and L3 for objective.
APPEARS IN
RELATED QUESTIONS
A person with a normal near point (25 cm) using a compound microscope with the objective of focal length 8.0 mm and an eyepiece of focal length 2.5 cm can bring an object placed at 9.0 mm from the objective in sharp focus. What is the separation between the two lenses? Calculate the magnifying power of the microscope.
An angular magnification (magnifying power) of 30X is desired using an objective of focal length 1.25 cm and an eyepiece of focal length 5 cm. How will you set up the compound microscope?
Define resolving power of a microscope and write one factor on which it depends
The magnifying power of a converging lens used as a simple microscope is `(1+D/f).` A compound microscope is a combination of two such converging lenses. Why don't we have magnifying power `(1+D/f_0)(1+D/f_0)`?In other words, why can the objective not be treated as a simple microscope but the eyepiece can?
A compound microscope consists of an objective of focal length 1 cm and an eyepiece of focal length 5 cm. An object is placed at a distance of 0.5 cm from the objective. What should be the separation between the lenses so that the microscope projects an inverted real image of the object on a screen 30 cm behind the eyepiece?
compound microscope consists of two convex lenses of focal length 2 cm and 5 cm. When an object is kept at a distance of 2.1 cm from the objective, a virtual and magnified image is fonned 25 cm from the eye piece. Calculate the magnifying power of the microscope.
Define the magnifying power of a microscope in terms of visual angle.
In the case of a regular prism, in minimum deviation position, the angle made by the refracted ray (inside the prism) with the normal drawn to the refracting surface is ______.
A thin converging lens of focal length 5cm is used as a simple microscope. Calculate its magnifying power when image formed lies at:
- Infinity.
- Least distance of distinct vision (D = 25 cm).
On increasing the focal length of the objective, the magnifying power ______.