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500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04m3? - Mathematics

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प्रश्न

500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04m3?

योग

उत्तर


Let the rise of water level in the pond be hm, when 500 persons are taking a dip into a cuboidal pond.

Given that,

Length of the cuboidal pond = 80 m

Breadth of the cuboidal pond = 50 m

Now, volume for the rise of water level in the pond

= Length × Breadth × Height

= 80 × 50 × h

= 4000h m3

And the average displacement of the water by a person = 0.04 m3

So, the average displacement of the water by 500 persons = 500 × 0.04 m3

Now, by given condition,

Volume for the rise of water level in the pond = Average displacement of the water by 500 persons

⇒ 4000h = 500 × 0.04

∴ h = `(500 xx 0.04)/4000`

= `20/4000`

= `1/200 "m"`

= 0.005 m

= 0.005 × 100 cm

= 0.5 cm

Hence, the required rise of water level in the pond is 0.5 cm.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Surface Areas and Volumes - Exercise 12.4 [पृष्ठ १५१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 12 Surface Areas and Volumes
Exercise 12.4 | Q 10 | पृष्ठ १५१

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