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A Solid is in the Form of a Right Circular Cone Mounted on a Hemisphere. the Radius of the Hemisphere is 2.1 Cm and the Height of the Cone is 4 Cm. the Solid is Placed in a Cylindrical - Mathematics

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प्रश्न

A solid is in the form of a right circular cone mounted on a hemisphere. The radius of the hemisphere is 2.1 cm and the height of the cone is 4 cm. The solid is placed in a cylindrical tub full of water in such a way that the whole solid is submerged in water. If the radius of the cylinder is 5 cm and its height is 9.8 cm, find the volume of the water left in the tub.

योग

उत्तर

The object is shown in the figure below. 

Radius of hemisphere = 2.1 cm

Volume of hemisphere = `2/3 pir^3 = 2/3 xx 22/7 xx2.1xx2.1=19.404  "cm"^3`

Height of cone = 4 cm 

Volume of cone = `1/3 pir^2h =1/3xx22/7xx2.1xx2.1xx 4=18.48   "cm"^3 `

When the object is immersed in the tub, volume of water equal to the volume of the object is displaced from the tub.

Volume of water left in the tub = 770 - 37.884 = 732.116 cm

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अध्याय 19: Volume and Surface Area of Solids - Exercise 19A [पृष्ठ ८७६]

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 19 Volume and Surface Area of Solids
Exercise 19A | Q 21 | पृष्ठ ८७६

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