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A Solid is in the Shape of a Cone Surmounted on a Hemisphere, the Radius of Each of Them Being 3.5 Cm and the Total Height of the Solid is 9.5 Cm. Find the Volume of the Solid. - Mathematics

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प्रश्न

A solid is in the shape of a cone surmounted on a hemisphere, the radius of each of them being 3.5 cm and the total height of the solid is 9.5 cm. Find the volume of the solid.

योग

उत्तर

We have,

Radius of cone = radius of hemisphere =r = 3.5 cm or AD = BD = CI

Total height of the solid, OC = 9.5 cm 

`rArr OD + CD = 9.5`

`rArr OD + 3.5 = 9.5` 

`rArr OD = 6  cm`

⇒ Height of cone, h = 6 cm

Now,

Volume of solid = Volume of cone + Volume of hemisphere

`= 1/3pir^2h + 2/3pir^3`

`=1/3 pir^2 (h + 2r)`

`=1/3xx22/7xx3.5xx3.5xx(6+2xx3.5)`

`= 1/3xx 22/7xx3.5xx3.5xx(6+7)`

`= 1/3xx22/7xx3.5xx3.5xx13`

`= 500.5/3`

≈ 166.83 cm

So, the volume of the solid is 166.83 cm3. 

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अध्याय 19: Volume and Surface Area of Solids - Exercise 19A [पृष्ठ ८७५]

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 19 Volume and Surface Area of Solids
Exercise 19A | Q 13 | पृष्ठ ८७५

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