हिंदी

In the Equilateral δ Abc of Side 14 Cm, Side Bc is the Diameter of a Semicircle as Shown in the Figure Below. Find the Area of the Shaded Region. (Take π = 22/7 and √3 = 1.732) - Mathematics

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प्रश्न

In the equilateral Δ ABC of side 14 cm, side BC is the diameter of a semicircle as shown in the figure below. Find the area of the shaded region. (Take π = 22/7 and √3 = 1.732)

योग

उत्तर

Area of shaded part = Area of equilateral Δ ABC + Area of semicircle
= `sqrt3/4 a^2 + 1/2` πr2

Given a = 14 cm and r = `14/2` = 7 cm
∴  Area of shaded part = `sqrt3/4 xx 14^2 + 1/2 xx 22/7 xx 7 xx 7`

= `(1.732 xx 14 xx 14)/4 + 11 xx 7`

= 1.732 x 7 x 7 + 77 
= 84.868 + 77
= 161.868 sq.cm.

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अध्याय 17: Mensuration - Exercise 3

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आईसीएसई Mathematics [English] Class 10
अध्याय 17 Mensuration
Exercise 3 | Q 1

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