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A Company Manufactures Two Types of Novelty Souvenirs Made of Plywood. Souvenirs of Type a Require 5 Minutes Each for Cutting and 10 Minutes Each for Assembling. - Mathematics

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प्रश्न

A company manufactures two types of novelty souvenirs made of plywood. Souvenirs of type A
require 5 minutes each for cutting and 10 minutes each for assembling. Souvenirs of type B require 8 minutes each for cutting and 8 minutes each for assembling. There are 3 hours and 20 minutes available  for cutting and 4 hours available for assembling. The profit is Rs. 50 each for type A and Rs. 60 each  for type B souvenirs. How many souvenirs of each type should the company manufacture in order to  maximize profit? Formulate the above LPP and solve it graphically and also find the maximum profit. 

योग

उत्तर १

Let no.of souvenirs of type A to be manufactured = x 

Type B = y. 

Type 

Quant.  Profit  Cutting time A.T 
A x 50 5min  10min
B y 60 8min  8min

Total time for cutting = 3h 20min
                                   =  200min
Total time for Assembling = 240 min
Profit =  50x +  60y (this is obj function)
5x + 8y ≤ 200               .....(i)
10x + 8y ≤ 240            .....(ii)
Also x, y ≥ 0

Corner points  Value of objective
O(0,0) 0
B(8 , 20)  400 + 1200 = 1600
A(0 , 25) 

1500

C (24 , 0)  1200

So the maximum profit is obtained by producing 8 units of A and 20 units of B  And max. profit is Rs. 1600

shaalaa.com

उत्तर २

Let the company manufacture x souvenirs of type A and y souvenirs of type B. Therefore,
x ≥ 0 and y ≥ 0
The given information can be complied in a table as follows.

  Type A Type B Availability
Cutting (min) 5 8 3 x 60 + 20 = 200
Assembling (min) 10 8 4 x 60 = 240

The profit on type A souvenirs is Rs 50 and on type, B souvenirs is Rs 60. Therefore, the constraints are i.e.,
5x + 8y ≤ 200.
10x + 8y ≤ 240 i.e., 5x + 4y ≤ 120
Total profit, Z = 50x + 60y

The mathematical formulation of the given problem is
Maximize Z = 50x + 60y ..… (1)
subject to the constraints,
5x + 8y ≤ 200   ..… (2)
5x + 4y ≤ 120   ..… (3)
x, y ≥ 0 ..… (4)

The feasible region determined by the system of constraints is as follows.

The corner points are A (24, 0), B (8, 20), and C (0, 25).
The values of Z at these corner points are as follows.

Corner point  Z = 50x + 60y  
A (24, 0) 1200  
B (8, 20) 1600 → Maximum
C (0, 25) 1500  

The maximum value of Z is 1600 at (8, 20).

Thus, 8 souvenirs of type A and 20 souvenirs of type B should be produced each day to get the maximum profit of Rs 1600.

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2018-2019 (March) 65/3/3

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