Advertisements
Advertisements
प्रश्न
A footpath of uniform width runs all around the outside of a rectangular field 30 m long and 24 m wide. If the path occupies an area of 360 m2, find its width.
उत्तर
Let x be the width of the footpath.
Then
Area of footpath = `2 xx ( 30 + 24 )x + 4x^2`
= 4x2 + 108x
Again it is given that the area of the footpath is 360sq.m.
Hence,
4x2 + 108x = 360
x2 + 27x - 90 = 0
( x - 3 )( x + 30 ) = 0
x = 3
Hence width of the footpath is 3m.
APPEARS IN
संबंधित प्रश्न
The diagonal of a rectangular plot is 34 m and its perimeter is 92 m. Find its area.
The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.
The diagonals of a quadrilateral are 16 cm and 13 cm. If they intersect each other at right angles; find the area of the quadrilateral.
Calculate the area of the figure given below: which is not drawn scale.
The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.
Find the area and perimeter of a square plot of land, the length of whose diagonal is 15 meters. Given your answer correct to 2 places of decimals.
A triangle and a parallelogram have the same base and the same area. If the side of the triangle is 26 cm, 28 cm, and 30 cm and the parallelogram stands on the base 28 cm, find the height of the parallelogram.
Vertices of given triangles are taken in order and their areas are provided aside. Find the value of ‘p’.
Vertices | Area (sq.units) |
(0, 0), (p, 8), (6, 2) | 20 |
In the following, find the value of ‘a’ for which the given points are collinear
(2, 3), (4, a) and (6, – 3)
When proving that a quadrilateral is a trapezium, it is necessary to show