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A Hollow Cylindrical Box of Length 1 M and Area of Cross-section 25 Cm2 is Placed in a Three Dimensional Coordinate System as Shown in the Figure. - Physics

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प्रश्न

A hollow cylindrical box of length 1 m and area of cross-section 25 cm2 is placed in a three dimensional coordinate system as shown in the figure. The electric field in the region is given by `vecE = 50xhati` where E is NC­−1 and x is in metres. Find

(i) Net flux through the cylinder.

(ii) Charge enclosed by the cylinder.

उत्तर

Given,`vecE = 50xhati and Δs = 25 cm^2 = 25 xx 10^-4 m^2`

As the electric field is only along the x-axis, so, flux will pass only through the cross-section of cylinder.

magnitude of electric field at cross - section A,`E_A = 50 xx 1 =50N C^-1`

magnitude of electric field at cross - section `B,E^B = 50 xx 2 = 100 N C^-1`

The corresponding electric fluxes are :

`ø_A = vecE.Δvecs = 50 xx 25 xx 10^-4 xx cos 180° = -0.125 N m^2 C^-1`

`ø_A = vecE.Δvecs = 100 xx 25 xx 10^-4 xx cos 0° = 0.25N m^2 C^-1`

So, the net flux through the cylinder,`ø =ø_A +ø_B = -0.125 + 0.25 = 0 . 125 N m^2C^-1 `

(ii) Using Gauss’s law:  `ointvecE.dvecs =q/in_0⇒ 0.125 = q/(8.85 xx 10^-12)⇒ q=8.85 xx 0.125 xx 10^-12 =1.1 xx 10 ^-12 C `

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Electric Field - Electric Field Due to a System of Charges
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2012-2013 (March) Delhi Set 2

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