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A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps. Assume [Assume π=227] - Mathematics

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प्रश्न

A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

`["Assume "pi=22/7]`

 

योग

उत्तर

Radius (r) of conical cap = 7 cm

Height (h) of conical cap = 24 cm

Slant height (l) of conical cap = `sqrt(r^2+h^2)`

= `[sqrt((7)^2+(24)^2)] cm`

= `sqrt (576 + 49)  cm`

= `sqrt625  cm`

= 25 cm

Curved surface area of 1 conical cap = πrl

= `(22/7xx7xx25)cm^2`

= 550 cm2

Curved surface area of 10 such conical caps = (10 × 550) cm2 = 5500 cm2

Therefore, the required area of the sheet is 5500 cm2.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Surface Area and Volumes - Exercise 13.3 [पृष्ठ २२१]

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एनसीईआरटी Mathematics [English] Class 9
अध्याय 13 Surface Area and Volumes
Exercise 13.3 | Q 7 | पृष्ठ २२१

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