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A Particle Moves Along The X-axis as X = U (T − 2 S) + A (T − 2 S)2. (A) the Initial Velocity of the Particle Is U (B) the Acceleration of the Particle Is A - Physics

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प्रश्न

A particle moves along the X-axis as x = u (t − 2 s) + a (t − 2 s)2.
(a) the initial velocity of the particle is u
(b) the acceleration of the particle is a
(c) the acceleration of the particle is 2a
(d) at t = 2 s particle is at the origin.

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उत्तर

(c) the acceleration of the particle is 2a
(d) at t = 2 s, the particle is at the origin
Initial velocity = \[\left| \frac{d x}{d t} \right|_{t = 0}\]

\[\frac{d x}{d t} = u + 2a(t - 2s)\]
\[\left| \frac{d x}{d t} \right|_{t = 0} = u - 4\text{ as } \neq u\]
Acceleration = \[\frac{d^2 x}{d t^2} = 2a\]
At t = 2 s,
x = u(2 s − 2 s) + a (2 s − 2 s)2 = 0 (origin) 
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अध्याय 3: Rest and Motion: Kinematics - MCQ [पृष्ठ ५०]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 3 Rest and Motion: Kinematics
MCQ | Q 2 | पृष्ठ ५०

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