Advertisements
Advertisements
प्रश्न
A railway half ticket costs half the full fare, but the reservation charges are the same on a half ticket as on a full ticket. One reserved first class ticket from the station A to B costs Rs 2530. Also, one reserved first class ticket and one reserved first class half ticket from A to B costs Rs 3810. Find the full first class fare from station A to B, and also the reservation charges for a ticket.
उत्तर
Let the cost of full and half first-class fare be ₹ x and ₹ `x/2` respectively and reservation charges be ₹ y per ticket.
Case I: The cost of one reserved first-class ticket from the stations A to B = ₹ 2530
⇒ x + y = 2530 ......(i)
Case II: The cost of one reserved first-class ticket and one reserved first-class half ticket from stations A to B = ₹ 3810
⇒ `x + y + x/2 + y` = 3810
⇒ `(3x)/2 + 2y` = 3810
⇒ 3x + 4y = 7620 .....(ii)
Now, multiplying equation (i) by 4 and then subtracting from equation (ii), we get
(3x + 4y) – (4x + 4y) = 7620 – 10120
⇒ –x = –2500
⇒ x = 2500
On putting the value of x in equation (i), we get
2500 + y = 2530
⇒ y = 2530 – 2500
⇒ y = 30
Hence, full first class fare from stations A to B is ₹ 2500 and the reservation charge for the ticket is ₹ 30.
APPEARS IN
संबंधित प्रश्न
Solve the following system of equations by cross-multiplication method.
2x + 3y + 8 = 0
4x + 5y + 14 = 0
For which value of k will the following pair of linear equations have no solution?
3x + y = 1
(2k – 1)x + (k – 1)y = 2k + 1
Solve the following systems of equations:
`x + 2y = 3/2`
`2x + y = 3/2`
Solve the following systems of equations:
`3x - (y + 7)/11 + 2 = 10`
`2y + (x + 10)/7 = 10`
Solve the following systems of equations:
`1/(7x) + 1/(6y) = 3`
`1/(2x) - 1/(3y) = 5`
Solve each of the following systems of equations by the method of cross-multiplication
`(x + y)/(xy) = 2`
`(x - y)/(xy) = 6`
Solve the system of equations by using the method of cross multiplication:
2ax + 3by – (a + 2b) = 0,
3ax + 2by – (2a + b) = 0
If `|( 4,5), (m , 3)|` = 22, then find the value of m.
Solve the following pair of equations:
`x/3 + y/4 = 4, (5x)/6 - y/4 = 4`
A shopkeeper sells a saree at 8% profit and a sweater at 10% discount, thereby, getting a sum Rs 1008. If she had sold the saree at 10% profit and the sweater at 8% discount, she would have got Rs 1028. Find the cost price of the saree and the list price (price before discount) of the sweater.