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A Small Metal Plate (Work Function φ) is Kept at a Distance D from a Singly-ionised, Fixed Ion. a Monochromatic Light Beam is Incident on the Metal Plate and Photoelectrons Are Emitted. - Physics

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प्रश्न

A small metal plate (work function φ) is kept at a distance d from a singly-ionised, fixed ion. A monochromatic light beam is incident on the metal plate and photoelectrons are emitted. Find the maximum wavelength of the light beam, so that some of the photoelectrons may go round the ion along a circle.

योग

उत्तर

From Einstein's photoelectric equation ,

`eV_0 = (hc)/lambda - phi`

⇒ `V_0 = ((hc)/lambda - phi)1/e`

Here, V0 = stopping potential
            h = Planck's constant
            c = speed of light
            `phi ` = work function

The particle will move in a circle when the stopping potential is equal to the potential due to the singly charged ion at that point so that the particle gets the required centripetal force for its circular motion.

`⇒ (Ke)/(2d) = ((hc)/lambda - phi)1/e`

`⇒ (Ke^2)/(2d) = (hc)/lambda - phi`

`⇒ (hc)/lambda = (Ke^2)/(2d) + phi = (Ke^2+2dphi)/(2d)`

`⇒ lambda = ((hc)(2d))/(ke^2+2dphi)`

`⇒ lambda = (2hdc)/(1/(4pi∈_0)e^2+2dphi`

`⇒ lambda = (8pi∈_0hcd)/(e^2+8pi∈_0dphi)`

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Einstein’s Photoelectric Equation: Energy Quantum of Radiation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 20: Photoelectric Effect and Wave-Particle Duality - Exercises [पृष्ठ ३६६]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 20 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 34 | पृष्ठ ३६६

संबंधित प्रश्न

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.


In an accelerator experiment on high-energy collisions of electrons with positrons, a certain event is interpreted as annihilation of an electron-positron pair of total energy 10.2 BeV into two γ-rays of equal energy. What is the wavelength associated with each γ-ray? (1BeV = 109 eV)


Write Einstein’s photoelectric equation?


Is p − E/c valid for electrons?


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The electric field at a point associated with a light wave is `E = (100  "Vm"^-1) sin [(3.0 xx 10^15 "s"^-1)t] sin [(6.0 xx 10^15 "s"^-1)t]`.If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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The minimum energy required to remove an electron is called ______.


The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly ______.


  1. In the explanation of photo electric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as Emax = hν – φ where φ0 is the work function of the metal. If an electron absorbs 2 photons (each of frequency ν) what will be the maximum energy for the emitted electron?
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A student performs an experiment on photoelectric effect, using two materials A and B. A plot of Vstop vs ν is given in Figure.

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Surface A: no photoemission occurs

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Surface C: photo emission occurs and photoelectrons have some kinetic energy.
Using Einstein’s photo-electric equation, explain the three observations.


A photon of wavelength 663 nm is incident on a metal surface. The work function of the metal is 1.50 eV. The maximum kinetic energy of the emitted photoelectrons is ______.


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