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A solid metallic cylinder is cut into two identical halves along its height (as shown in the diagram). The diameter of the cylinder is 7 cm and the height is 10 cm - Mathematics

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प्रश्न

A solid metallic cylinder is cut into two identical halves along its height (as shown in the diagram). The diameter of the cylinder is 7 cm and the height is 10 cm.

Find:

  1. The total surface area (both the halves).
  2. The total cost of painting the two halves at the rate of ₹ 30 per cm2 `("Use"  π = 22/7)`.
योग

उत्तर

Here, radius of cylinder (r) = `7/2` cm   ...(∴ d = 7 cm)

Height of cylinder = 10 cm

a. T.S.A of a half cylinder

`(πr^2)/2 + (πr^2)/2 + (2πrh)/2 + d xx h`

= `πr^2 + πrh + d xx h`

= `22/7 xx  7/2 xx 7/2 + 22/7 xx 7/2 xx 10 + 7 xx 10`

= `77/2 + 110 + 70`

= `77/2 + 180`

= `(77 + 360)/2`

= `437/2`

= 218.5 cm2

 So, total surface area of each half is 218.5 cm2.

b. Cost of painting = Total surface area × Rate of painting

= (218.5 + 218.5) × 30

= ₹ 13,110

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