Advertisements
Advertisements
प्रश्न
A truck covers a distance of 150 km at a certain average speed and then covers another 200 km at an average speed which is 20 km per hour more than the first speed. If the truck covers the total distance in 5 hours, find the first speed of the truck.
उत्तर
Let the original speed of the truck = s km/hr
New speed of the truck = (s + 20) km/hr
Time taken for 150 km + Time taken for 200 km = 5
`150/s+200/(s+20)=5`
`(150s+3000+200s)/(s(s+20))=5`
`(350s+3000)/(s(s+20))=5`
`(50(7s+60))/(s(s+20))=5`
`10(7s+ 60) =s(s+20)`
70s+600 = s2 + 20s
s2 - 50s - 600 =0
s2 - 60s -10s- 600 =0
(s - 10)(s - 60) = 0
s =10,60
s =10[Not possible]
First speed of the truck = 60 km/hr
APPEARS IN
संबंधित प्रश्न
The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is
`(A) 50sqrt3`
`(B) 150sqrt 3`
`(C) 150sqrt2`
`(D) 75`
If the angle of elevation of cloud from a point 200 m above a lake is 30º and the angle of depression of its reflection in the lake is 60º, then find the height of the cloud above the lake
From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 45° and 60° respectively. Find the height of the tower. (Use `sqrt3` = 1.73)
From an aeroplane vertically above a straight horizontal road, the angles of depression of two consecutive milestones on opposite sides of the aeroplane are observed to be α and β. Show that the height in miles of the aeroplane above the road is given by `(tan alpha tan beta)/(tan alpha + tan beta)`
A tower stands vertically on the ground. From a point on the ground which is 20 m away from the foot of the tower, the angle of elevation of its top is found to be 60°. Find the height of the tower. [Take `sqrt(3)` =1.732 ]
A vertical tower stands on a horizontal plane and is surmounted by a flagstaff of height 5 m. From a point on the ground the angles of elevation of the top and bottom of the flagstaff are 60° and 30° respectively. Find the height of the tower and the distance of the point from the tower. (take\[\sqrt{3}\]= 1.732)
The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 60 m high, find the height of the building.
If the height of a tower and the distance of the point of observation from its foot, both, are increased by 10%, then the angle of elevation of its top ____________.
If the height of a tower and the distance of the point of observation from its foot, both, are increased by 10%, then the angle of elevation of its top remains unchanged.
If one looks from a tower 10 m high at the top of a flag staff, the depression angle of 30° is made. Also, looking at the bottom of the staff from the tower, the angle of the depression made is of 60°. Find the height of the flag staff.