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A Wire, Fixed at Both Ends is Seen to Vibrate at a Resonant Frequency of 240 Hz and Also at 320 Hz. (A) What Could Be the Maximum Value of the Fundamental Frequency? - Physics

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प्रश्न

A wire, fixed at both ends is seen to vibrate at a resonant frequency of 240 Hz and also at 320 Hz. (a) What could be the maximum value of the fundamental frequency? (b) If transverse waves can travel on this string at a speed of 40 m s−1, what is its length?

योग

उत्तर

Given:
Wire makes a resonant frequency of 240 Hz and 320 Hz when its both ends are fixed.
Therefore, fundamental frequency (f0) of the wire must be the factor of 240 Hz and 320 Hz.
(a) Maximum value of fundamental frequency, f0 = 80 Hz

(b) Wave speed (v) = 40 m/s
And if λ  is  the  wave length:
λ2=L

v=λ×f0 

v=2×L×f0 

L=402×80 

L=14m=0.25m

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Wave Motion and Waves on a String - Exercise [पृष्ठ ३२६]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 15 Wave Motion and Waves on a String
Exercise | Q 41 | पृष्ठ ३२६

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