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प्रश्न
Δ ABC ∼ Δ PQR such that AB= 1.5 cm and PQ=2. 1 cm. Find the ratio of areas of Δ ABC and ΔPQR.
उत्तर
To find : `("Ar" triangle "ABC")/("Ar" triangle "PQR") = "AB"^2/"PQ"^2`
[The ration of areas of two similar triangle is equal to the ratio of square of their corresponding sides.]
`= (1.8/2.1)^2`
`= (6/7)^2`
`= 36/49`
Required ratio = 36 : 49.
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