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An Urn Contains 4 Red and 7 Black Balls. Two Balls Are Drawn at Random with Replacement. Find the Probability of Getting 2 Red Balls. - Mathematics

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प्रश्न

An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 2 red balls.  

योग

उत्तर

\[\text{ Total balls = 4 red balls + 7 blue balls = 11 balls } \]
\[ P\left( 2 \text{ red balls } \right) = P\left( \text{ first ball is red }  \right) \times P\left( \text{ second ball is red } \right)\]
\[ = \frac{4}{11} \times \frac{4}{11}\]
\[ = \frac{16}{121}\]

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Probability Examples and Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 31: Probability - Exercise 31.4 [पृष्ठ ५४]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 31 Probability
Exercise 31.4 | Q 22.1 | पृष्ठ ५४

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