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Question
An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 2 red balls.
Solution
\[\text{ Total balls = 4 red balls + 7 blue balls = 11 balls } \]
\[ P\left( 2 \text{ red balls } \right) = P\left( \text{ first ball is red } \right) \times P\left( \text{ second ball is red } \right)\]
\[ = \frac{4}{11} \times \frac{4}{11}\]
\[ = \frac{16}{121}\]
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