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Question
In a shop X, 30 tins of pure ghee and 40 tins of adulterated ghee which look alike, are kept for sale while in shop Y, similar 50 tins of pure ghee and 60 tins of adulterated ghee are there. One tin of ghee is purchased from one of the randomly selected shops and is found to be adulterated. Find the probability that it is purchased from shop Y. What measures should be taken to stop adulteration?
Solution
Let A be the event that the ghee is adulterated.
Shop X contains 30 pure ghee container and 40 adultered container.
∴ Probability of adultered ghee container = P(A/X) = \[\frac{40}{70} = \frac{4}{7}\]
∴ Probability of adultered ghee container = P(A/Y) = \[\frac{60}{110} = \frac{6}{11}\]
Required Probability, P(Y/A)
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