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Question
Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that both the balls are red.
Solution
\[\text{ Given : Box } = \left( 10B + 8R \right) \text{ balls } \]
\[ P\left( \text{ both red balls }\right) = \frac{8}{18} \times \frac{8}{18}\]
\[ = \frac{64}{324} = \frac{16}{81}\]
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