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Question
Two dice are thrown simultaneously. The probability of getting a pair of aces is
Options
\[\frac{1}{36}\]
\[\frac{1}{3}\]
\[\frac{1}{6}\]
none of these
Solution
\[ \frac{1}{36}\]
\[P\left( \text{ pair of aces } \right) = P\left( \text{ ace in first throw } \right) \times P\left( \text{ ace in second throw } \right)\]
\[ = \frac{1}{6} \times \frac{1}{6}\]
\[ = \frac{1}{36}\]
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