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Question
Find the chance of drawing 2 white balls in succession from a bag containing 5 red and 7 white balls, the ball first drawn not being replaced.
Solution
Consider the given events.
A = A white ball in the first draw
B = A white ball in the second draw
\[\text{ Now }, \]
\[P\left( A \right) = \frac{7}{12}\]
\[P\left( B/A \right) = \frac{6}{11}\]
\[ \therefore \text{ Required probability } = P\left( A \cap B \right) = P\left( A \right) \times P\left( B/A \right) = \frac{7}{12} \times \frac{6}{11} = \frac{7}{22}\]
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