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An Urn Contains Four White and Three Red Balls. Find the Probability Distribution of the Number of Red Balls in Three Draws with Replacement from the Urn. - Mathematics

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प्रश्न

An urn contains four white and three red balls. Find the probability distribution of the number of red balls in three draws with replacement from the urn.

योग

उत्तर

As three balls are drawn with replacement, the number of white balls, say X, follows binomial distribution with n =3

\[p = \frac{3}{7} \text{ and } q = \frac{4}{7}\]
\[P(X = r) = ^{3}{}{C}_r \left( \frac{3}{7} \right)^r \left( \frac{4}{7} \right)^{3 - r} , r = 0, 1, 2, 3\]
\[P(X = 0) = ^{3}{}{C}_0 \left( \frac{3}{7} \right)^0 \left( \frac{4}{7} \right)^{3 - 0} \]
\[ P(X = 1) = ^{3}{}{C}_1 \left( \frac{3}{7} \right)^1 \left( \frac{4}{7} \right)^{3 - 1} \]
\[P(X = 2) = ^{3}{}{C}_2 \left( \frac{3}{7} \right)^2 \left( \frac{4}{7} \right)^{3 - 2} \]
\[P(X = 3) = ^{3}{}{C}_3 \left( \frac{3}{7} \right)^3 \left( \frac{4}{7} \right)^{3 - 3} \]
  X         0     1      2      3
\[P(X) \                        \frac{64}{343} \frac{144}{343} \frac{108}{343} \frac{27}{343}\]

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अध्याय 33: Binomial Distribution - Exercise 33.1 [पृष्ठ १३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 33 Binomial Distribution
Exercise 33.1 | Q 21 | पृष्ठ १३

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