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Suppose a random variable X follows the binomial distribution with parameters n and p, where 0 < p < 1. If P(x = r)/P(x = n – r) is independent of n and r, then p equals ______. - Mathematics

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प्रश्न

Suppose a random variable X follows the binomial distribution with parameters n and p, where 0 < p < 1. If P(x = r)/P(x = n – r) is independent of n and r, then p equals ______.

विकल्प

  • `1/2`

  • `1/3`

  • `1/5`

  • `1/7`

MCQ
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उत्तर

Suppose a random variable X follows the binomial distribution with parameters n and p, where 0 < p < 1. If P(x = r)/P(x = n – r) is independent of n and r, then p equals `1/2`.

Explanation:

P(X = r) = `""^"n""C"_"r" "p"^"r" "q"^("n" - "r") = ("n"1)/("r"!("n" - "r")!) "p"^"r"*(1 - "p")^("n" - "r")`

P(X = n – r) = `""^"n""C"_("n" - "r") "p"^("n" - "r") * ("q")^("n" - ("n" - "r")`

= `""^"n""C"_("n" - "r") "p"^("n" - "r") * "q"^"r"`

= `("n"1)/(("n" - "r")!("n" - "n" + "r")!) "p"^("n" - "r")"q"^"r"`

= `("n"!)/(("n" - "r")!"r"!) * "p"^("n" - "r") * "q"^"r"`

Now `("P"(x = "r"))/("P"(x = "n" - "r"))`

= `(("n"!)/("r"!("n" - "r")!)*"p"^"r"*(1 - "p")^("n" - "r"))/(("n"!)/("r"!("n" - "r")!)*"p"^("n" - "r")*(1 - "p")^"r")`

= `((1 - "p")/"p")^("n" - "r")/((1 - "p")/"p")^"r"`

The above expression will be independent of n and r if

`((1 - "p")/"p")` = 1

⇒ `1/"p"` = 2

⇒ p = `1/2`

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अध्याय 13: Probability - Exercise [पृष्ठ २८४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 13 Probability
Exercise | Q 90 | पृष्ठ २८४

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