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Answer the following question: By using properties of determinant prove that |x+yy+zz+xzxy111| = 0 - Mathematics and Statistics

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प्रश्न

Answer the following question:

By using properties of determinant prove that `|(x + y, y + z, z + x),(z, x, y),(1, 1, 1)|` = 0

योग

उत्तर

L.H.S. = `|(x + y, y + z, z + x),(z, x, y),(1, 1, 1)|`

By R1 + R2 , we get,

L.H.S. = `|(x + y + z, x + y + z, x + y + z),(z, x, y),(1, 1, 1)|`

By taking (x + y + z) common from R1, we get,

L.H.S. = `(x + y + z)|(1, 1, 1),(z, x, y),(1, 1, 1)|` 

=(x + y + z) × 0  ...[∵ R1 ≡ R3]

= 0

= R.H.S.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Determinants and Matrices - Miscellaneous Exercise 4(A) [पृष्ठ ७६]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 4 Determinants and Matrices
Miscellaneous Exercise 4(A) | Q II. (6) | पृष्ठ ७६

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