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Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 112 times its abscissa. - Mathematics

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प्रश्न

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is `1 1/2` times its abscissa.

योग

उत्तर

Given: 2x + 5y = 19   ...(i)

Ordinate is `1 1/2` times its abscissa

⇒ `y = 1 1/2 x = 3/2 x`

Putting `y = 3/2x` in equation (i)

We have `2x + 5 3/2x = 19`

⇒ `19/2x = 19`

⇒ x = 2

Putting x = 2 in equation (i)

We have 2 × 2 + 5y = 19

`y = (19 - 4)/5 = 3`

Therefore, point (2, 3) is the required solution.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Linear Equation In Two Variables - Exercise 4.3 [पृष्ठ ३९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 4 Linear Equation In Two Variables
Exercise 4.3 | Q 2. | पृष्ठ ३९

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